Optimal. Leaf size=85 \[ \frac {2 B \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{\sqrt {b} e^{3/2}}-\frac {2 \sqrt {a+b x} (B d-A e)}{e \sqrt {d+e x} (b d-a e)} \]
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Rubi [A] time = 0.05, antiderivative size = 85, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {78, 63, 217, 206} \begin {gather*} \frac {2 B \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{\sqrt {b} e^{3/2}}-\frac {2 \sqrt {a+b x} (B d-A e)}{e \sqrt {d+e x} (b d-a e)} \end {gather*}
Antiderivative was successfully verified.
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Rule 63
Rule 78
Rule 206
Rule 217
Rubi steps
\begin {align*} \int \frac {A+B x}{\sqrt {a+b x} (d+e x)^{3/2}} \, dx &=-\frac {2 (B d-A e) \sqrt {a+b x}}{e (b d-a e) \sqrt {d+e x}}+\frac {B \int \frac {1}{\sqrt {a+b x} \sqrt {d+e x}} \, dx}{e}\\ &=-\frac {2 (B d-A e) \sqrt {a+b x}}{e (b d-a e) \sqrt {d+e x}}+\frac {(2 B) \operatorname {Subst}\left (\int \frac {1}{\sqrt {d-\frac {a e}{b}+\frac {e x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{b e}\\ &=-\frac {2 (B d-A e) \sqrt {a+b x}}{e (b d-a e) \sqrt {d+e x}}+\frac {(2 B) \operatorname {Subst}\left (\int \frac {1}{1-\frac {e x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {d+e x}}\right )}{b e}\\ &=-\frac {2 (B d-A e) \sqrt {a+b x}}{e (b d-a e) \sqrt {d+e x}}+\frac {2 B \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{\sqrt {b} e^{3/2}}\\ \end {align*}
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Mathematica [A] time = 0.31, size = 118, normalized size = 1.39 \begin {gather*} \frac {2 b \sqrt {e} \sqrt {a+b x} (B d-A e)-2 B (b d-a e)^{3/2} \sqrt {\frac {b (d+e x)}{b d-a e}} \sinh ^{-1}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b d-a e}}\right )}{b e^{3/2} \sqrt {d+e x} (a e-b d)} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.17, size = 85, normalized size = 1.00 \begin {gather*} \frac {2 B \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{\sqrt {b} e^{3/2}}-\frac {2 \sqrt {a+b x} (A e-B d)}{e \sqrt {d+e x} (a e-b d)} \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 2.23, size = 362, normalized size = 4.26 \begin {gather*} \left [\frac {{\left (B b d^{2} - B a d e + {\left (B b d e - B a e^{2}\right )} x\right )} \sqrt {b e} \log \left (8 \, b^{2} e^{2} x^{2} + b^{2} d^{2} + 6 \, a b d e + a^{2} e^{2} + 4 \, {\left (2 \, b e x + b d + a e\right )} \sqrt {b e} \sqrt {b x + a} \sqrt {e x + d} + 8 \, {\left (b^{2} d e + a b e^{2}\right )} x\right ) - 4 \, {\left (B b d e - A b e^{2}\right )} \sqrt {b x + a} \sqrt {e x + d}}{2 \, {\left (b^{2} d^{2} e^{2} - a b d e^{3} + {\left (b^{2} d e^{3} - a b e^{4}\right )} x\right )}}, -\frac {{\left (B b d^{2} - B a d e + {\left (B b d e - B a e^{2}\right )} x\right )} \sqrt {-b e} \arctan \left (\frac {{\left (2 \, b e x + b d + a e\right )} \sqrt {-b e} \sqrt {b x + a} \sqrt {e x + d}}{2 \, {\left (b^{2} e^{2} x^{2} + a b d e + {\left (b^{2} d e + a b e^{2}\right )} x\right )}}\right ) + 2 \, {\left (B b d e - A b e^{2}\right )} \sqrt {b x + a} \sqrt {e x + d}}{b^{2} d^{2} e^{2} - a b d e^{3} + {\left (b^{2} d e^{3} - a b e^{4}\right )} x}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.07, size = 120, normalized size = 1.41 \begin {gather*} -\frac {2 \, B {\left | b \right |} e^{\left (-\frac {3}{2}\right )} \log \left ({\left | -\sqrt {b x + a} \sqrt {b} e^{\frac {1}{2}} + \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e} \right |}\right )}{b^{\frac {3}{2}}} - \frac {2 \, {\left (B b^{2} d {\left | b \right |} - A b^{2} {\left | b \right |} e\right )} \sqrt {b x + a}}{{\left (b^{3} d e - a b^{2} e^{2}\right )} \sqrt {b^{2} d + {\left (b x + a\right )} b e - a b e}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 278, normalized size = 3.27 \begin {gather*} \frac {\left (B a \,e^{2} x \ln \left (\frac {2 b e x +a e +b d +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}}{2 \sqrt {b e}}\right )-B b d e x \ln \left (\frac {2 b e x +a e +b d +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}}{2 \sqrt {b e}}\right )+B a d e \ln \left (\frac {2 b e x +a e +b d +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}}{2 \sqrt {b e}}\right )-B b \,d^{2} \ln \left (\frac {2 b e x +a e +b d +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}}{2 \sqrt {b e}}\right )-2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, A e +2 \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {b e}\, B d \right ) \sqrt {b x +a}}{\sqrt {b e}\, \left (a e -b d \right ) \sqrt {\left (b x +a \right ) \left (e x +d \right )}\, \sqrt {e x +d}\, e} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {A+B\,x}{\sqrt {a+b\,x}\,{\left (d+e\,x\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {A + B x}{\sqrt {a + b x} \left (d + e x\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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